Searching but cannot find

[peethagoras]

This is probably the wrong place to ask, so I will apologise in advance, but could someone please assist?

I'm sure the subject of the two large letters K A at the end of the 154 sonnets has been discussed somewhere, but I cannot locate any such discussion. The K A is supposed to be a kind of printer's catchword,  but may have some hidden significance. Can anyone help please?

Many thanks.

[Light-of-Truth]

8 minutes ago, peethagoras said:

This is probably the wrong place to ask, so I will apologise in advance, but could someone please assist?

I'm sure the subject of the two large letters K A at the end of the 154 sonnets has been discussed somewhere, but I cannot locate any such discussion. The K A is supposed to be a kind of printer's catchword,  but may have some hidden significance. Can anyone help please?

Many thanks.

Sounds familiar, but I can't answer at the moment. Maybe after some digging in my brain storage.

[Allisnum2er]

I do not remember that we have already talked about this subject by the past.

[Light-of-Truth]

16 minutes ago, Allisnum2er said:

I do not remember that we have already talked about this subject by the past.

The "K A" rings a bell, but could be from long before the B'Hive. Dodd, Dawkins, Walkers, and more recently a while before the forum is Christie and A. Phoenix, etc.

I could have written something about the "K A" and don't remember! 😉

K and A is 10 1, it is the center of the ShaKAshA I like to use, "1881101881". My number time machine. LOL

KA is 11 Simple cipher, so here we are at the end of the Sonnets and there is an 11. Like so many places in the Sonnets, we pass 11 and it is like Two Pillars. I thought we were done at the end of Day 364, but do we pass beyond Two more Pillars with Day 365, the big fat O?

Do we start over and do it again? Every year? Do we read the Sonnets every day knowing where we are listening to Bacon's words while also aware of any numbers, and at the end after Sonnet 154 and Day 364, go through KA, first we see 101 (Two Pillars with a big fat O or Globe between them), then 11 (Two Pillars inviting us to pass), to repeat forever.

[Light-of-Truth]

This may be what I remember as this book has been very important for me:

https://sirbacon.org/archives/Secret_Shakesperean_Seals.pdf

[Allisnum2er]

5 minutes ago, Light-of-Truth said:

The "K A" rings a bell, but could be from long before the B'Hive. Dodd, Dawkins, Walkers, and more recently a while before the forum is Christie and A. Phoenix, etc.

I could have written something about the "K A" and don't remember! 😉

K and A is 10 1, it is the center of the ShaKAshA I like to use, "1881101881". My number time machine. LOL

KA is 11 Simple cipher, so here we are at the end of the Sonnets and there is an 11. Like so many places in the Sonnets, we pass 11 and it is like Two Pillars. I thought we were done at the end of Day 364, but do we pass beyond Two more Pillars with Day 365, the big fat O?

Do we start over and do it again? Every year? Do we read the Sonnets every day knowing where we are listening to Bacon's words while also aware of any numbers, and at the end after Sonnet 154 and Day 364, go through KA, first we see 101 (Two Pillars with a big fat O or Globe between them), then 11 (Two Pillars inviting us to pass), to repeat forever.

When I discovered the K1 cipher , playing with this new cipher,  I wondered if there was a link with the K A

Indeed, K A = K 1  , and by using the K1 cipher , as K = 16  then KA # 161 (For me, the compasse of the wise)

 

[Light-of-Truth]

12 minutes ago, Allisnum2er said:

Indeed, K A = K 1  , and by using the K1 cipher , as K = 16  then KA # 161 (For me, the compasse of the wise)

Compasse of the wise

One of your best posts for sure! Nice surprise on November 6 this past year.  🙂

[Light-of-Truth]

2 hours ago, peethagoras said:

This is probably the wrong place to ask, so I will apologise in advance, but could someone please assist?

Right forum, wrong area, but with this new Topic in Baconian Discussions we'll start with your post. 🙂

The new Forum is:

Bacon's Story; SHAKE-SPEARES SONNETS
Is Francis Bacon's life woven into Shakespeares Sonnets?

 

[peethagoras]

A big thank you to all who responded to my query.

I am now deeply involved with the subject and enjoying it all. 😁

 

[RoyalCraftiness]

On 2/3/2023 at 4:52 PM, Light-of-Truth said:

Sounds familiar, but I can't answer at the moment. Maybe after some digging in my brain storage.

153 is the perfect number of Biblical notoriety. A modern cultural reference: the Oak Island legends used that number for the depth of the vault (Enoch's vault before it plummeted into the abyss). 10 is the perfect number of the Greeks (an idea that comes out of the perfection of the decad in Antiquity). 153 and 1 and 10 and 1 are similar that way.

You are often helped by considering the proper factors in numbers given to you. 154 has 2,7 and 11. They sum to 20 (TT).  if you are quick on the draw you will see that 2x11/7is the ancient approximation of pi that comes out of the continued fraction expression. TT is of course pi when the two Tees are touching. It would not be surprising to see this involved in something which you have noticed has a pyramid shape reference. The pyramid with height equal to a multiple of phi is going to represent one half of an octahedron which you can fit in a circle/sphere. That pyramid will represent one half of a duality. The idea with the pyramid is that you can Hermetically project yourself into the heavens with it. I suppose one could see that as taking one step beyond the perfection of the material world. Taking that next step baby...it's a hard step to take, lol.

Edited February 26 by RoyalCraftiness

[Light-of-Truth]

2 hours ago, RoyalCraftiness said:

if you are quick on the draw you will see that 2x11/7is the ancient approximation of pi that comes out of the continued fraction expression.

I am slow on the draw. LOL

But I did know that 22/7 is considered pi. I did not realize that 11/7 is 1.57142857142... which has the same repeating numbers as pi 3.14285714285...

Now I see 33/7 and 44/7 so on share the same repeating numbers.

111, 222, 444, 666 etc. up to 999 divided by 7 all share the pattern.

I am exhausted and going to bed, but may dream of numbers. Maybe some Angels will share some revelations with me. But at this moment I am very happy with revelations shared by humans. 🙂

 

 

[RoyalCraftiness]

14 hours ago, Light-of-Truth said:

I am slow on the draw. LOL

But I did know that 22/7 is considered pi. I did not realize that 11/7 is 1.57142857142... which has the same repeating numbers as pi 3.14285714285...

Now I see 33/7 and 44/7 so on share the same repeating numbers.

111, 222, 444, 666 etc. up to 999 divided by 7 all share the pattern.

I am exhausted and going to bed, but may dream of numbers. Maybe some Angels will share some revelations with me. But at this moment I am very happy with revelations shared by humans. 🙂

 

 

That has to be that way. 10/7=1+0.4285714285714285714285714285714.... No matter what you divide by seven (unless it is a multiple of seven) it will produce a decimal remainder which will eventually become expressed by a remainder of 10/7.

2/7= 0 + next digits equal to 20/7 = 0.2 + next digits equal to 60/7=0.28 +next digit equal to 40/7=0.285+ next digits equal to 50/7=0.2857+next digits equal to 10/7=0.2587(1 + 0.428571428571....)

There's a mathematical proof to show that all rational numbers (integer fractions) can be expressed by decimal expressions with a repeating decimal part. Irrational numbers are by definition numbers with no repeating decimal part. All fractional approximations of pi will have a repeating part. Pi never will.

223 is prime, by the way. Its the 48th prime. Prime numbers were considered equivalent to primal matter. If you divide the precession period by 48 it yields 540 which is the sum of the internal angles in a pentagon. The precession cycle does have 5 demarcations which coincide with the occurrence of the 5 pole stars which form a pentagon around the constellation of Draco. It's all nice coincidences to potentially strive to see meaning in if you are Hermetic minded soul. In a regular pentagon each angle is 108 which is the perimeter of the perfect stone ashlar of Freemasonry (the square of side=27=3^3).  It was known pretty early on that the distance from Earth to Moon is 108 times the moon's diameter. You can start to see how celestial bodies and cycles take on the symbolism of polygons. Dee's pentagon in a heptagon arrangement is way to suggest overlapping cycles of 7 and 5. An example of a cycle based in 7 was the old Hepton eclipse cycle.

[Light-of-Truth]

11 minutes ago, RoyalCraftiness said:

That has to be that way. 10/7=1+0.4285714285714285714285714285714.... No matter what you divide by seven (unless it is a multiple of seven) it will produce a decimal remainder which will eventually become expressed by a remainder of 10/7.

Punching my calculator buttons I see you are absolutely correct. I had no idea it was so simple!

5/7 = 0.714285714285714285...

12/7 = 1.714285714285714285...

I feel silly. Its a simple magic trick that always works out! LOL

14 minutes ago, RoyalCraftiness said:

223 is prime, by the way. Its the 48th prime. Prime numbers were considered equivalent to primal matter. If you divide the precession period by 48 it yields 540 which is the sum of the internal angles in a pentagon. The precession cycle does have 5 demarcations which coincide with the occurrence of the 5 pole stars which form a pentagon around the constellation of Draco. It's all nice coincidences to potentially strive to see meaning in if you are Hermetic minded soul.

Something caught my attention this morning that set me forth looking for Bacon/Dee connections. The only fact so far is that they met on Day 223 in 1582, August 11th.

I may write a post or reply later today on this topic and explain what I read that triggered my search.

 

[RoyalCraftiness]

7 hours ago, Light-of-Truth said:

Punching my calculator buttons I see you are absolutely correct. I had no idea it was so simple!

5/7 = 0.714285714285714285...

12/7 = 1.714285714285714285...

I feel silly. Its a simple magic trick that always works out! LOL

Something caught my attention this morning that set me forth looking for Bacon/Dee connections. The only fact so far is that they met on Day 223 in 1582, August 11th.

I may write a post or reply later today on this topic and explain what I read that triggered my search.

 

Consider this: 365-223= 142 remaining days

That remainder can be expressed in sexagesimal as 2, 22

Every 4th year you would add 1 day and get 2, 23

 

 

Edited February 28 by RoyalCraftiness

[Light-of-Truth]

7 hours ago, RoyalCraftiness said:

Consider this: 365-223= 142 remaining days

That remainder can be expressed in sexagesimal as 2, 22

Every 4th year you would add 1 day and get 2, 23

OK, I get 142 as minutes is 2 hours and 22 minutes.

So, in a 360 Day year...hmmm...

120 Days plus 22 Days (or 23 every four years). 60 Days is 1/6 of the sexagesimal year. 120 (or 2) is 1/3, then 2, 22 is plus 22.

I guess the first 2 is 120 sexagesimal (2x60) like 2 in the tens column in a decimal system is 20 (2x10). So 2, 22 is 120 + 22.

Maybe I get it. I'm surprised we don't learn that in High School school in America!

I remember learning hexadecimal in my first real computer tech school in 1978.

0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, and F converts to 0 through 15. That is based on Bacon's binary system with 4 bits. Zero is 0000 (aaaa) and F is 1111 (bbbb). 1000 is 16, or 10 in hex.

😉

 

[RoyalCraftiness]

1 hour ago, Light-of-Truth said:

OK, I get 142 as minutes is 2 hours and 22 minutes.

So, in a 360 Day year...hmmm...

120 Days plus 22 Days (or 23 every four years). 60 Days is 1/6 of the sexagesimal year. 120 (or 2) is 1/3, then 2, 22 is plus 22.

I guess the first 2 is 120 sexagesimal (2x60) like 2 in the tens column in a decimal system is 20 (2x10). So 2, 22 is 120 + 22.

Maybe I get it. I'm surprised we don't learn that in High School school in America!

I remember learning hexadecimal in my first real computer tech school in 1978.

0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, and F converts to 0 through 15. That is based on Bacon's binary system with 4 bits. Zero is 0000 (aaaa) and F is 1111 (bbbb). 1000 is 16, or 10 in hex.

😉

 

That's right. The integer part is just dividing by 60 and  putting the remainder after the comma. It gets more interesting with decimals.

The year 365 would be expressed as 6,5

The exact year 365.2588 or 365 + 279457/1080000 (nice appearance of 108) would be 6,5;15,31,41,24 in cuneiform

222 is 3, 42

142 is 2, 22

242 is 4,2

Cute isn't it?  Forty-two is that number that Lewis Carroll goes batty over.

 

 

Edited February 28 by RoyalCraftiness